How to Pass All Terminal Arguments to Another Program in Bash

In Bash, we can use $@ to quickly pass all arguments we received in one script to another script or program. For example, let's say we have the following code:

#!/usr/bin/env bash
echo You passed me: $@

If we save this as script.sh, make it executable, and run it like this:

chmod +x ./script.sh
./script.sh first second third fourth

This is what we'll get as output:

You passed me: first second third fourth

Observe that the zeroth argument ($0: the program's name) isn't passed when we use $@.

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